Engineering Mechanics of SolidsPopov (civil engineering, U. Cal., Berkeley) has written this textbook for undergraduate students. Traditional topics are supplemented by an exposure to several newly-emerging disciplines, such as the probabilistic basis for structural analysis, and matrix methods. Annotation copyright Book News, In |
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... caused by shear . Let E = 70 GPa . Solution A unit virtual force of 1 kN is applied vertically downward at C. This force causes an axial force in member DB and in part AB of the beam , Fig . 12-8 ( b ) . Owing to this force , bending ...
... caused by shear . Let E = 70 GPa . Solution A unit virtual force of 1 kN is applied vertically downward at C. This force causes an axial force in member DB and in part AB of the beam , Fig . 12-8 ( b ) . Owing to this force , bending ...
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... caused by bending in relation to that caused by shear . The following example is concerned with such a problem , where in the solution , it is assumed that the force is gradually applied . By contrast , in the second example , an impact ...
... caused by bending in relation to that caused by shear . The following example is concerned with such a problem , where in the solution , it is assumed that the force is gradually applied . By contrast , in the second example , an impact ...
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... caused by the bending moment stresses must be maintained in equilibrium by a force in the dowel . The force that must be resisted can be evaluated by summing the forces in the axial direction caused by bending stresses . In performing ...
... caused by the bending moment stresses must be maintained in equilibrium by a force in the dowel . The force that must be resisted can be evaluated by summing the forces in the axial direction caused by bending stresses . In performing ...
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A₁ allowable stress aluminum analysis angle applied force applied load assumed axes axial force axially loaded bar beam bending moment bending stress bolts buckling C₁ caused centroid column compression concentrated force considered constant cross section cross-sectional area cylinder deflection deformations Determine diameter direction elastic curve elastic modulus element equal equations equilibrium example figure flange flexure formula given by Eq Hence Hooke's law horizontal in² indeterminate problems inertia infinitesimal internal kips length linearly elastic material maximum shear stress mm² modulus Mohr's circle moment of inertia neutral axis normal stress obtained P₁ plane plastic principal stresses problem procedure reactions rectangular rotation segment shaft shear center shear stress shown in Fig solution statically indeterminate steel strain energy stress distribution stress-strain stresses acting tensile tensile stress Tmax torque torsion tube vertical yield zero