Strength of Materials

algebraic sum angle Answer axial load beam shown bending moment bending-moment diagram center of gravity compression member computed concentrated load couple cross section Determine diameter distance elastic curve equal equation equilibrium factor of safety fibers fillet weld flexure stress free body ft long ft-kips ft-lb horizontal Illustrative Problem in-lb in.³ inertia joint kips lb Fig lb per sq length located longitudinal M/EI diagram M₁ M₂ magnitude material maximum allowable maximum deflection maximum shearing unit method Mohr's circle moment of inertia neutral axis normal stress obtained P₁ perpendicular plane portion position principal stresses produced R₁ R₂ radius reaction restraining moments resultant section A-A shaft shear area shear diagram shearing stress shearing unit stress shown in Fig simple beam slope SOLUTION statically indeterminate steel strength strength of materials stresses acting tangential deviation tensile stress tensile unit stress tension thickness torque torsion unit strain zero ΕΙ