Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 38
... Given the two vectors A = 1-4 ✰ + 2ŷ + 32 and B = 4 - 5ŷ + 62 , find the angle between them . Find the component of A in the direction of B. B = 6x Given the vectors A = 2 + 39-42 and 4ŷ +2 . Find the component of A × B along the ...
... Given the two vectors A = 1-4 ✰ + 2ŷ + 32 and B = 4 - 5ŷ + 62 , find the angle between them . Find the component of A in the direction of B. B = 6x Given the vectors A = 2 + 39-42 and 4ŷ +2 . Find the component of A × B along the ...
Page 39
... given by : ( 0 , 0 ) → ( 3,0 ) → ( 3,4 ) → 4 ) - >> ( 0 , 0 ) . Also calculate the surface integral of × A over the enclosed area and show that ( 1-67 ) is satisfied . + ( 0 , 1-15 Given the vector field A = x2yî + xy2ŷ a3e - By cos ...
... given by : ( 0 , 0 ) → ( 3,0 ) → ( 3,4 ) → 4 ) - >> ( 0 , 0 ) . Also calculate the surface integral of × A over the enclosed area and show that ( 1-67 ) is satisfied . + ( 0 , 1-15 Given the vector field A = x2yî + xy2ŷ a3e - By cos ...
Page 275
... given by ( 17-3 ) . We find the flux in the same manner as we used to get ( 17-14 ) : Φ • = √2 [ B B. ǹ da S = Boab cos o = Boab cos ( wt + o ) Substituting this into ( 17-3 ) , we find the induced emf to be & = ind wBoab sin ( wt + ...
... given by ( 17-3 ) . We find the flux in the same manner as we used to get ( 17-14 ) : Φ • = √2 [ B B. ǹ da S = Boab cos o = Boab cos ( wt + o ) Substituting this into ( 17-3 ) , we find the induced emf to be & = ind wBoab sin ( wt + ...
Contents
INTRODUCTION | 1 |
ELECTRIC MULTIPOLES | 8 |
Electrostatic Forces | 103 |
Copyright | |
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Ampère's law angle assume axis becomes bound charge boundary conditions calculate capacitance capacitor charge density charge distribution charge q circuit conductor consider const constant corresponding Coulomb's law current density curve cylinder defined dielectric dipole direction displacement distance divergence theorem E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example expression field point flux force function given induction infinitely long integral integrand line charge located Lorentz transformation magnetic magnitude Maxwell's equations obtained parallel particle perpendicular plane wave plates point charge polarized position vector quantities region result scalar potential Section shown in Figure solenoid sphere of radius spherical surface integral tangential components theorem total charge vacuum vector potential velocity volume write written xy plane zero Απερ μο