Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 104
... equal and opposite to the charge on the other . Accordingly , we take for our general definition of a capacitor the following : any two conductors with equal and opposite charges Q and - Q. Even so , it is not immediately evident that ...
... equal and opposite to the charge on the other . Accordingly , we take for our general definition of a capacitor the following : any two conductors with equal and opposite charges Q and - Q. Even so , it is not immediately evident that ...
Page 181
... equal the vacuum value : D = Do = of ( 10-61 ) This result is also consistent with ( 10-42 ) since the fields are zero inside the conducting plate and therefore D2n - D1n = D - 0 = 0 . The electric field has changed , however , since we ...
... equal the vacuum value : D = Do = of ( 10-61 ) This result is also consistent with ( 10-42 ) since the fields are zero inside the conducting plate and therefore D2n - D1n = D - 0 = 0 . The electric field has changed , however , since we ...
Page 333
... equal to zero , increase i , from 0 to I , while keeping all the others zero . Then , with I , at its final value , increase i1⁄2 from 0 to 12 and so on for each in turn . In this way , show that ( 18-6 ) is again obtained . 18-4 Use ...
... equal to zero , increase i , from 0 to I , while keeping all the others zero . Then , with I , at its final value , increase i1⁄2 from 0 to 12 and so on for each in turn . In this way , show that ( 18-6 ) is again obtained . 18-4 Use ...
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Ampère's law angle assume axis becomes bound charge boundary conditions bounding surface calculate capacitance capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density curve cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point flux force free charge free currents frequency function given induction infinitely long integral integrand k₂ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector potential difference quadrupole quantities radiation radius rectangular region result satisfy scalar scalar potential shown in Figure solenoid sphere spherical tangential components unit vacuum vector potential velocity volume write written xy plane zero Απερ дх Мо