Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 22
... Integral Consider a surface S ; as shown in Figure 1-29 , we can divide S into vector elements of area da as ... integral of A over S and is given by ↓ A cos seda = SA · ña - SA · ñda = SA - da ( 1-56 ) This integral is also called the ...
... Integral Consider a surface S ; as shown in Figure 1-29 , we can divide S into vector elements of area da as ... integral of A over S and is given by ↓ A cos seda = SA · ña - SA · ñda = SA - da ( 1-56 ) This integral is also called the ...
Page 24
... integrals are taken over the total surface S and throughout the volume V whose volume element is dr . Again , for convenience , we have written the volume integral with a single integral sign although in reality it is a triple integral ...
... integrals are taken over the total surface S and throughout the volume V whose volume element is dr . Again , for convenience , we have written the volume integral with a single integral sign although in reality it is a triple integral ...
Page 267
... integral of B about some closed path . 15-1 Derivation of the Integral Form We will show that фва 3.ds = Holenc ( 15-1 ) where the integral is taken about an arbitrary closed path C and Ienc is the total current passing through the area ...
... integral of B about some closed path . 15-1 Derivation of the Integral Form We will show that фва 3.ds = Holenc ( 15-1 ) where the integral is taken about an arbitrary closed path C and Ienc is the total current passing through the area ...
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Ampère's law angle assume axis becomes bound charge boundary conditions bounding surface calculate capacitance capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density curve cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point flux force free charge free currents frequency function given induction infinitely long integral integrand k₂ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector potential difference quadrupole quantities radiation radius rectangular region result satisfy scalar scalar potential shown in Figure solenoid sphere spherical tangential components unit vacuum vector potential velocity volume write written xy plane zero Απερ дх Мо