Mechanics of Materials |
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Page 263
... kip / ft 6 kip / ft 18 ft ( a ) 36 kip 36 kip 4 kip / ft } 2 kip / ft 9 ft - 12 ft 18 ft 30 kip 42 kip 1 x ( b ) + ↑ ΣF , = 0 ; 30 kip – ( 2 kip / ft ) x - - ( 4 kip / ft ) x- - V = 0 18 ft 2x 늘 ( 4 ) ( 주 ) X ( 1 ) Η ΣΜΝΑ = 0 ; v = ( 30- ...
... kip / ft 6 kip / ft 18 ft ( a ) 36 kip 36 kip 4 kip / ft } 2 kip / ft 9 ft - 12 ft 18 ft 30 kip 42 kip 1 x ( b ) + ↑ ΣF , = 0 ; 30 kip – ( 2 kip / ft ) x - - ( 4 kip / ft ) x- - V = 0 18 ft 2x 늘 ( 4 ) ( 주 ) X ( 1 ) Η ΣΜΝΑ = 0 ; v = ( 30- ...
Page 278
... kip / ft ( a ) A B C D 4 ft 6ft 4 ft ( b ) A 4.40 kip 8 kip B 2 kip / ft - 6 ft —— 4 ft → ↓ D 17.6 kip Slope = -2 V ( kip ) Slope = 0 8 4.40 ( c ) Slope = 0 -3.60 -9.60 M ( kip - ft ) , ( d ) 17.6 Slope = -3.60 Slope = 4.40 ( e ) -4 ...
... kip / ft ( a ) A B C D 4 ft 6ft 4 ft ( b ) A 4.40 kip 8 kip B 2 kip / ft - 6 ft —— 4 ft → ↓ D 17.6 kip Slope = -2 V ( kip ) Slope = 0 8 4.40 ( c ) Slope = 0 -3.60 -9.60 M ( kip - ft ) , ( d ) 17.6 Slope = -3.60 Slope = 4.40 ( e ) -4 ...
Page 628
R. C. Hibbeler. Example 12-16 k = 15 kip / ft - 3 ft - 3 kip C ( a ) || 6 ft B The steel bar shown in Fig . 12-33a is supported by two springs at its ends A and B. Each spring has a stiffness of k = 15 kip / ft and is originally ...
R. C. Hibbeler. Example 12-16 k = 15 kip / ft - 3 ft - 3 kip C ( a ) || 6 ft B The steel bar shown in Fig . 12-33a is supported by two springs at its ends A and B. Each spring has a stiffness of k = 15 kip / ft and is originally ...
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allowable shear stress aluminum angle of twist Applying Eq average normal stress axes axial force axial load beam's bolt buckling caused centroid column compressive computed constant cross section cross-sectional area deflection deformation Determine the maximum diameter distributed load elastic curve element Example factor of safety free-body diagram ft Prob Hooke's law inē inertia kip/ft kN·m kN/m length linear-elastic loading shown located material maximum bending stress maximum in-plane shear maximum shear stress modulus of elasticity Mohr's circle moment of inertia neutral axis normal strain plane stress plastic principal stresses radius reactions sectional area segment shaft shear flow shear force shear strain shown in Fig SOLUTION Solve Prob statically indeterminate steel strain energy stress acting stress at points stress components stress distribution stress-strain diagram thickness Tmax torque torsional tube vertical yield zero ΕΙ