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The current density J has only a component in the $ direction , Jp = 18 ( cos 09 0
( r ' – a ) ( 5.33 ) a The delta functions restrict current flow to a ring of radius a .
Only a $ component of J means that A will have only a component also . But this ...
If we assume that to be the only component of E , then it must be a constant , E.
Because the moving fluid will tend to carry the lines of force with it , we expect an
x component B. ( z ) of magnetic induction , as well as the z component Bo .
But we have just seen that for comparable parallel and perpendicular forces the
radiation from the parallel component is negligible ( of order 1/72 ) compared to
that from the perpendicular component . Consequently we may neglect the ...
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Introduction to Electrostatics
BoundaryValue Problems in Electrostatics I
Multipoles Electrostatics of Macroscopic Media
4 other sections not shown