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The current density J has only a component in the <f> direction, J+ = /<5(cos 6') 6
(r' ~ a) (5.33) a The delta functions restrict current flow to a ring of radius a. Only a
<f> component of J means that A will have only a <f> component also. But this ...
If we assume that to be the only component of E, then it must be a constant, E0.
Because the moving fluid will tend to carry the lines of force with it, we expect an
x component Bx(z) of magnetic induction, as well as the z component B0.
But we have just seen that for comparable parallel and perpendicular forces the
radiation from the parallel component is negligible (of order 1/y2) compared to
that from the perpendicular component. Consequently we may neglect the
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Introduction to Electrostatics
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