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The current density J has only a component in the <j> direction, J+ = /<5(cos 0') 6
(r' ~ a) (5.33) The delta functions restrict current flow to a ring of radius a. Only a <
f> component of J means that A will have only a <f> component also. But this ...
Writing out a single component of f, we find A = pE1 + - (J2B3 - J3B2) = - (F12J2 +
F1SJ3 + F14J4) (11.127) c c where we have used definitions ( 1 1 .98) and ( 1 1 .
1 08). The other components of f yield similar results, showing that (11.126) ...
But we have just seen that for comparable parallel and perpendicular forces the
radiation from the parallel component is negligible (of order 1/y2) compared to
that from the perpendicular component. Consequently we may neglect the
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Introduction to Electrostatics
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