## Classical ElectrodynamicsProblems after each chapter |

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... 1 y + pp + 70 135.0 Since the photon has no rest

... 1 y + pp + 70 135.0 Since the photon has no rest

**mass**, the**mass**difference is AM = M40 = 135.0 Mev , while the target**mass**is m , = m , = 938.5 Mev .Page

PROBLEMS 15.1 A nonrelativistic particle of charge e and

PROBLEMS 15.1 A nonrelativistic particle of charge e and

**mass**m collides with a fixed , smooth , hard sphere of radius R. Assuming that the collision is ...Page

15.3 Two identical point particles of charge q and

15.3 Two identical point particles of charge q and

**mass**m interact by means of a short - range repulsive interaction which is equivalent to a hard sphere of ...### What people are saying - Write a review

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### Contents

Introduction to Electrostatics | 1 |

Greens theorem | 14 |

BoundaryValue Problems in Electrostatics I | 26 |

Copyright | |

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### Common terms and phrases

acceleration angle angular applied approximation assumed atomic average axis becomes boundary conditions calculate called Chapter charge charged particle classical collisions compared component conducting Consequently consider constant coordinates cross section cylinder defined density dependence derivative determine dielectric dimensions dipole direction discussed distance distribution effects electric field electromagnetic electron electrostatic energy equal equation example expansion expression factor force frame frequency function given gives incident inside integral involved limit Lorentz loss magnetic magnetic field magnetic induction magnitude mass means momentum motion moving multipole normal observation obtain origin parallel particle physical plane plasma polarization position potential problem properties radiation radius region relation relative relativistic result satisfy scalar scattering shown in Fig shows side solution sphere spherical surface transformation unit vanishes vector velocity volume wave written