## Classical Electrodynamics |

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Page 18

In obtaining result (1.36)—not a solution—we chose the function p to be 1/|x – x',

it being the potential of a unit point charge,

x"| = —4trö(x — x') (1.31) The function 1/|x – x' is only one of a class of functions ...

In obtaining result (1.36)—not a solution—we chose the function p to be 1/|x – x',

it being the potential of a unit point charge,

**satisfying**the equation: Vo2 s 1 ) |x —x"| = —4trö(x — x') (1.31) The function 1/|x – x' is only one of a class of functions ...

Page 181

To see that potentials can always be found to

suppose that the potentials A, D which

6.36). Then let us make a gauge transformation to potentials A', 'b' and demand

that A', ...

To see that potentials can always be found to

**satisfy**the Lorentz condition,suppose that the potentials A, D which

**satisfy**(6.32) and (6.33) do not**satisfy**(6.36). Then let us make a gauge transformation to potentials A', 'b' and demand

that A', ...

Page 183

Then b = 0, and A

given by E = - 1% c 0t (6.53) B = W x A 6.6 Green's Function for the Time-

Dependent Wave Equation The wave equations (6.37), (6.38), and (6.52) all

have the basic ...

Then b = 0, and A

**satisfies**the homogeneous wave equation. The fields aregiven by E = - 1% c 0t (6.53) B = W x A 6.6 Green's Function for the Time-

Dependent Wave Equation The wave equations (6.37), (6.38), and (6.52) all

have the basic ...

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### Contents

Introduction to Electrostatics | 1 |

Nº 3 | 3 |

Greens theorem | 14 |

Copyright | |

30 other sections not shown

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