## Classical Electrodynamics |

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Page 111

The surface may be taken as the plane z = 0, as

the appropriate solution to the equations: eIV - E = 4mp, z > 0 l e.V. E = 0, 2 < 0 (

4.47) and V x E = 0, everywhere subject to the boundary conditions at z = 0: | e1E

, ...

The surface may be taken as the plane z = 0, as

**shown in Fig**. 4.5. We must findthe appropriate solution to the equations: eIV - E = 4mp, z > 0 l e.V. E = 0, 2 < 0 (

4.47) and V x E = 0, everywhere subject to the boundary conditions at z = 0: | e1E

, ...

Page 117

... that for atoms in a simple cubic lattice s = 0 at any lattice site. The argument

depends on the symmetry of the problem, as can be seen as follows. Suppose

that inside the sphere we have a cubic array of dipoles such as are

... that for atoms in a simple cubic lattice s = 0 at any lattice site. The argument

depends on the symmetry of the problem, as can be seen as follows. Suppose

that inside the sphere we have a cubic array of dipoles such as are

**shown in Fig**.Page 155

pillbox is oriented so that its faces are in regions 1 and 2 and parallel to the

surface boundary, S, as

B = 0 to yield (B2 - B). n = 0 (5.88) where n is the unit normal to the surface

directed ...

pillbox is oriented so that its faces are in regions 1 and 2 and parallel to the

surface boundary, S, as

**shown in Fig**. 5.9, Gauss's theorem can be applied to V.B = 0 to yield (B2 - B). n = 0 (5.88) where n is the unit normal to the surface

directed ...

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### Contents

Introduction to Electrostatics | 1 |

Greens theorem | 14 |

BoundaryValue Problems in Electrostatics I | 26 |

Copyright | |

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