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If the path is closed, the line integral is zero, # e.a. = 0 (1.21) a result that can also
be obtained directly from Coulomb's law. Then application of Stokes's theorem [if
A(x) is a vector field, S is an open surface, and C is the closed curve bounding ...
The tangential component of electric field can be shown to be continuous across
a boundary surface by using (1.21) for the line integral of E around a closed path.
It is only necessary to take a rectangular path with negligible ends and one side ...
John David Jackson, Patrick Thaddeus Jackson. of the conductor. According to
Ohm's law, there exists a current density J near the surface of the conductor: J =
ore = *0. – i)(n x Ho)e^*** (8.13) 7. The time-average rate of dissipation of energy
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Introduction to Electrostatics
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