Classical Electrodynamics |
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Page 19
... vanishes and the solution is q}(x) = | 2006/s ×) or -4. f ox)*da (144) P 477 JS 0n'
For Neumann boundary conditions we ... x') seems to be 3GN (x, x') = 0 for x' on S
0n' since that makes the second term in the surface integral in (1.42) vanish, ...
... vanishes and the solution is q}(x) = | 2006/s ×) or -4. f ox)*da (144) P 477 JS 0n'
For Neumann boundary conditions we ... x') seems to be 3GN (x, x') = 0 for x' on S
0n' since that makes the second term in the surface integral in (1.42) vanish, ...
Page 282
(9.64) With this condition on p it can readily be seen that the integral in (9,63)
over the hemisphere S, vanishes inversely as the hemisphere radius as that
radius goes to infinity. Then we obtain the Kirchhoff integral for p(x) in region II: 1
ik R x) ...
(9.64) With this condition on p it can readily be seen that the integral in (9,63)
over the hemisphere S, vanishes inversely as the hemisphere radius as that
radius goes to infinity. Then we obtain the Kirchhoff integral for p(x) in region II: 1
ik R x) ...
Page 284
(GE))] dor' (9.74) y From the expansion, V × V × A = V(V - A) — W*A, it is evident
that the volume integral vanishes identically.” With the surface integral of the first
three terms in (9.72) identically zero, the remaining three terms give an ...
(GE))] dor' (9.74) y From the expansion, V × V × A = V(V - A) — W*A, it is evident
that the volume integral vanishes identically.” With the surface integral of the first
three terms in (9.72) identically zero, the remaining three terms give an ...
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Contents
Introduction to Electrostatics | 1 |
Nē 3 | 3 |
Greens theorem | 14 |
Copyright | |
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acceleration angle angular applied approximation assumed atomic average axis becomes boundary conditions calculate called Chapter charge classical collisions compared component conducting conductor Consequently consider constant coordinates cross section cylinder defined density depends derivative determine dielectric dimensions dipole direction discussed distance distribution effects electric field electromagnetic electron electrostatic energy equal equation example expansion expression factor force frame frequency function given gives incident inside integral involved limit Lorentz loss magnetic magnetic field magnetic induction magnitude mass means momentum motion moving multipole normal observation obtain origin parallel particle physical plane plasma polarization position potential problem properties radiation radius region relation relative result satisfy scalar scattering shows side simple solution space sphere spherical surface transformation unit vanishes vector velocity volume wave written
Bibliographic information
| Title | Classical Electrodynamics |
| Author | John David Jackson |
| Publisher | Wiley, 1963 |
| Length | 641 pages |
| Export Citation | BiBTeX EndNote RefMan |