Introduction to Mechanics of Deformable Solids |
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Page 55
Therefore , at each stage in the twisting deformation the circle remains a circle
with the central angle between any two points unchanged . Axial symmetry does
not rule out a change in radius or an axial displacement , nor does it restrict the ...
Therefore , at each stage in the twisting deformation the circle remains a circle
with the central angle between any two points unchanged . Axial symmetry does
not rule out a change in radius or an axial displacement , nor does it restrict the ...
Page 228
This plane makes an angle of 30° counterclockwise with the plane on which the
10 , 000 - psi stress acts . Therefore the corresponding point on the circle is on
the radial line from the center which makes an angle of twice 30° , or 60° ...
This plane makes an angle of 30° counterclockwise with the plane on which the
10 , 000 - psi stress acts . Therefore the corresponding point on the circle is on
the radial line from the center which makes an angle of twice 30° , or 60° ...
Page 231
The line joining the two plotted points is a diameter of the circle , because the
planes represented are at right angles . ... The orientation of the principal planes
is given by the angle a , 01 02 21 tan 2a ( 11.2 : 13 ) 02 The angle a between the
x ...
The line joining the two plotted points is a diameter of the circle , because the
planes represented are at right angles . ... The orientation of the principal planes
is given by the angle a , 01 02 21 tan 2a ( 11.2 : 13 ) 02 The angle a between the
x ...
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actual addition angle answer applied assemblage axial axis beam behavior bending circle circular column combined components compression compressive stress computed Consider constant creep cross section curve cylinder deflection deformation determined diameter direction displacement effect elastic equal equation equilibrium example Figure Find force given gives homogeneous idealization increase initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires residual response result rotation shaft shear stress shell shown shows simple sketch solid solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled torsion tube twisting uniform unloading viscous yield zero