## Introduction to Mechanics of Deformable Solids |

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Page 55

outward along the radius , all points on the

amount . Similarly , the circumferential displacement of each of the points of the

outward along the radius , all points on the

**circle**must move outward by the sameamount . Similarly , the circumferential displacement of each of the points of the

**circle**must be the same . Therefore , at each stage in the twisting deformation ...Page 228

The line joining points 1 and 3 is a diameter of the Mohr ' s

components of stress acting on any plane perpendicular to the plane of the paper

. Two points are sufficient to determine the

the on ...

The line joining points 1 and 3 is a diameter of the Mohr ' s

**circle**for thecomponents of stress acting on any plane perpendicular to the plane of the paper

. Two points are sufficient to determine the

**circle**, because its center must lie onthe on ...

Page 230

6 ) ( d )

calculation is simple and direct and should not be skipped . The result , however ,

can be written down without going through the entire process of summation of

forces ...

6 ) ( d )

**Circle**is traced out as B goes from 0 to 180° ( see Fig . 11 . 8 ) . Thecalculation is simple and direct and should not be skipped . The result , however ,

can be written down without going through the entire process of summation of

forces ...

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actual addition angle answer applied assemblage axial axis beam behavior bending circle circular column combined components compression compressive stress computed Consider constant creep cross section curve cylinder deflection deformation determined diameter direction displacement effect elastic equal equation equilibrium example Figure Find force given gives homogeneous idealization increase initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires residual response result rotation shaft shear stress shell shown shows simple sketch solid solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled torsion tube twisting uniform unloading viscous yield zero