## Introduction to Mechanics of Deformable Solids |

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Page 101

In the absence of external force , R = 0 , a temperature increase oc alone will

cause forces Pi , and Per given by the equations Pie + P = 0 equilibrium PL

deformation condition or geometric

AE , Pie ...

In the absence of external force , R = 0 , a temperature increase oc alone will

cause forces Pi , and Per given by the equations Pie + P = 0 equilibrium PL

deformation condition or geometric

**compatibility**so that Pe L L VLO . A t QILO . =AE , Pie ...

Page 177

By this time , the steps taken to solve a statics problem in the mechanics of

deformable solids are a well - established routine . The equations of equilibrium ,

the conditions of deformation or

must be ...

By this time , the steps taken to solve a statics problem in the mechanics of

deformable solids are a well - established routine . The equations of equilibrium ,

the conditions of deformation or

**compatibility**, and the stress - strain relationsmust be ...

Page 381

... all these examples , the fact that virtual work simply puts equilibrium and

equilibrium relation upon substitution of any set of displacements and compatible

strains .

... all these examples , the fact that virtual work simply puts equilibrium and

**compatibility**side by side , independently , is reflected by the obtaining of anequilibrium relation upon substitution of any set of displacements and compatible

strains .

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### Common terms and phrases

actual addition angle answer applied assemblage axes axial axis beam behavior bending circle circular column combined compatibility components compression compressive stress Consider constant creep cross section curve cylinder deflection deformation determined diameter direction displacement effect elastic equal equation equilibrium example Figure Find force given gives homogeneous idealization increase initial interior isotropic length limit linear linear-elastic load material maximum Maxwell modulus moment needed nonlinear normal obtained outer plane plastic positive pressure principal Prob problem produced pure radius range ratio relation replaced requires residual response result rotation shaft shear stress shell shown shows simple sketch solid solution steel strain stress-strain relations structural Suppose surface symmetry temperature tensile tension thickness thin-walled torsion tube twisting uniform unloading versus viscous yield zero