## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

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Page 105

In this case, dU, = dUe where Ue is the capacitor energy and (7-36) becomes F.--

1-A (S-

function of the plate separation, C = C(x), and therefore Q1 dUe-~^2 dC C7"38) ...

In this case, dU, = dUe where Ue is the capacitor energy and (7-36) becomes F.--

1-A (S-

**const**.) (7-37) dx Q Now Ue = Q2/2C according to (7-21), but since C is afunction of the plate separation, C = C(x), and therefore Q1 dUe-~^2 dC C7"38) ...

Page 172

We assume that, in addition to satisfying Laplace's equation, <f> is constant on all

points of the bounding surface S: <t> =

1-115), (1-45), (1-17), and (11-3), we find that V • (<t> V</>) = V</> . V<//> + ...

We assume that, in addition to satisfying Laplace's equation, <f> is constant on all

points of the bounding surface S: <t> =

**const**. on boundary (11-4) Now if we use (1-115), (1-45), (1-17), and (11-3), we find that V • (<t> V</>) = V</> . V<//> + ...

Page 534

Let us use rectangular coordinates and let B = B% where B =

while vx = vji + vyy and we find that (A-ll) gives dt dvx qB dt win y dvy ~dt qB m. (A

-22) From the first of these we obtain vz = v0z =

Let us use rectangular coordinates and let B = B% where B =

**const**. Then v|( = vzlwhile vx = vji + vyy and we find that (A-ll) gives dt dvx qB dt win y dvy ~dt qB m. (A

-22) From the first of these we obtain vz = v0z =

**const**. so that z = z0 + v0zt.### What people are saying - Write a review

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### Common terms and phrases

angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conducting conductor const constant corresponding Coulomb's law current density curve cylinder dielectric dipole direction displacement distance divergence theorem electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux free charge function given illustrated in Figure induction infinitely long integral integrand Laplace's equation line charge located Lorentz transformation magnetic magnitude Maxwell's equations normal component obtained origin parallel plate capacitor particle perpendicular point charge polarized position vector potential difference quadrupole quantities rectangular coordinates region result satisfy scalar potential shown in Figure situation solenoid solution sphere of radius spherical surface charge surface charge density surface integral tangential components theorem total charge vacuum vector potential velocity volume write written xy plane zero