## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

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Page 19

Roald K. Wangsness. Figure 1-26. Determination of the components of a vector

area element. given, in rectangular coordinates, by the product of the

as written, ...

Roald K. Wangsness. Figure 1-26. Determination of the components of a vector

area element. given, in rectangular coordinates, by the product of the

**corresponding**differentials. Since we always treat these differentials as positiveas written, ...

Page 120

A point dipole at the origin and parallel to the z axis. dipole potential as p cos 8 "

MO = 1 2 (8"48) The equation giving the equipotential surfaces

<f>D = const. is thus r2=( — — |cos0 = CDcos0 (8-49) where the constant CD ...

A point dipole at the origin and parallel to the z axis. dipole potential as p cos 8 "

MO = 1 2 (8"48) The equation giving the equipotential surfaces

**corresponding**to<f>D = const. is thus r2=( — — |cos0 = CDcos0 (8-49) where the constant CD ...

Page 454

This requirement determines y that is found to be R R *•' 2L 1 LC 1/2 R = + 8 2L ~

(27-13) so that there are two possible values of y. We write them as y + and y _

This requirement determines y that is found to be R R *•' 2L 1 LC 1/2 R = + 8 2L ~

(27-13) so that there are two possible values of y. We write them as y + and y _

**corresponding**, respectively, to the plus and minus signs in (27-13). For each ...### What people are saying - Write a review

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angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conducting conductor const constant corresponding Coulomb's law current density curve cylinder dielectric dipole direction displacement distance divergence theorem electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux free charge function given illustrated in Figure induction infinitely long integral integrand Laplace's equation line charge located Lorentz transformation magnetic magnitude Maxwell's equations normal component obtained origin parallel plate capacitor particle perpendicular point charge polarized position vector potential difference quadrupole quantities rectangular coordinates region result satisfy scalar potential shown in Figure situation solenoid solution sphere of radius spherical surface charge surface charge density surface integral tangential components theorem total charge vacuum vector potential velocity volume write written xy plane zero