## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

### From inside the book

Results 1-3 of 85

Page 39

results. 1-14 Calculate directly the line integral ^A • ds of the vector A = -yx + xy

around the closed path in the xy plane with straight sides given by: (0, 0) - (3, ...

**Evaluate**/v • A dr over the volume of this same parallelepiped and compare yourresults. 1-14 Calculate directly the line integral ^A • ds of the vector A = -yx + xy

around the closed path in the xy plane with straight sides given by: (0, 0) - (3, ...

Page 103

If one has found E by other means, then one can

such a case Ue will turn out to be proportional to Q2 or <f>2 or (A<//>)2,

depending on what is given, so that when Ue is found in this way, it can be

immediately ...

If one has found E by other means, then one can

**evaluate**(7-28). We know that insuch a case Ue will turn out to be proportional to Q2 or <f>2 or (A<//>)2,

depending on what is given, so that when Ue is found in this way, it can be

immediately ...

Page 261

Do not

general expression for A, find integral expressions for the components of B, and

then ...

Do not

**evaluate**the integral. Now assume that the field point is on the z axis and**evaluate**the integral to find A at any point on the axis. Now go back to thegeneral expression for A, find integral expressions for the components of B, and

then ...

### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Other editions - View all

### Common terms and phrases

angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conducting conductor const constant corresponding Coulomb's law current density curve cylinder dielectric dipole direction displacement distance divergence theorem electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux free charge function given illustrated in Figure induction infinitely long integral integrand Laplace's equation line charge located Lorentz transformation magnetic magnitude Maxwell's equations normal component obtained origin parallel plate capacitor particle perpendicular point charge polarized position vector potential difference quadrupole quantities rectangular coordinates region result satisfy scalar potential shown in Figure situation solenoid solution sphere of radius spherical surface charge surface charge density surface integral tangential components theorem total charge vacuum vector potential velocity volume write written xy plane zero