## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

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Page 263

We also assume the presence of an induction B so that there will be a

through the surface 5 enclosed by C. If we arbitrarily choose a sense of traversal

about C as indicated by the arrow, this will define the direction of the element of

area ...

We also assume the presence of an induction B so that there will be a

**flux**$through the surface 5 enclosed by C. If we arbitrarily choose a sense of traversal

about C as indicated by the arrow, this will define the direction of the element of

area ...

Page 278

circuit Cj, then the

as „,-fA.<„).*□-£$$i^i (17-44) We see that the

current Ik in Ck. If we give this factor of proportionality the symbol MJk and call it ...

circuit Cj, then the

**flux**through C, due to Ck will be given by (16-23) and (16-10)as „,-fA.<„).*□-£$$i^i (17-44) We see that the

**flux**through C is proportional to thecurrent Ik in Ck. If we give this factor of proportionality the symbol MJk and call it ...

Page 280

If the coil is tightly wound on the solenoid surface, we can take the cross-

sectional area of it to be approximately the same as that of the solenoid, S. Then

since Bs is normal to the plane of S, the

BSS ...

If the coil is tightly wound on the solenoid surface, we can take the cross-

sectional area of it to be approximately the same as that of the solenoid, S. Then

since Bs is normal to the plane of S, the

**flux**per turn of the coil will be Oturn =BSS ...

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angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conducting conductor const constant corresponding Coulomb's law current density curve cylinder dielectric dipole direction displacement distance divergence theorem electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux free charge function given illustrated in Figure induction infinitely long integral integrand Laplace's equation line charge located Lorentz transformation magnetic magnitude Maxwell's equations normal component obtained origin parallel plate capacitor particle perpendicular point charge polarized position vector potential difference quadrupole quantities rectangular coordinates region result satisfy scalar potential shown in Figure situation solenoid solution sphere of radius spherical surface charge surface charge density surface integral tangential components theorem total charge vacuum vector potential velocity volume write written xy plane zero