## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

### From inside the book

Results 1-3 of 87

Page 39

1-14 Calculate directly the line integral ^A • ds of the vector A = -yx + xy around

the closed path in the xy plane with straight sides

(0, 4) - (0, 0). Also calculate the surface integral of V X A over the enclosed area ...

1-14 Calculate directly the line integral ^A • ds of the vector A = -yx + xy around

the closed path in the xy plane with straight sides

**given**by: (0, 0) - (3, 0) - (3, 4) -»(0, 4) - (0, 0). Also calculate the surface integral of V X A over the enclosed area ...

Page 275

Let us first find the induced emf from the overall view

flux in the same manner as we used to get (17-14): $ = (B hda = B0ab cosy =

B0abcos(ut + <p0) (17-36) Js Substituting this into (17-3), we find the induced

emf to ...

Let us first find the induced emf from the overall view

**given**by (17-3). We find theflux in the same manner as we used to get (17-14): $ = (B hda = B0ab cosy =

B0abcos(ut + <p0) (17-36) Js Substituting this into (17-3), we find the induced

emf to ...

Page 551

... dipole moment for equilibrium conditions at a

involve a result from statistical mechanics that says that the probability of finding

a system in a

-22) ...

... dipole moment for equilibrium conditions at a

**given**temperature, we mustinvolve a result from statistical mechanics that says that the probability of finding

a system in a

**given**quantum state of energy Wm is**given**by *JWm) = ^£_ptVm (B-22) ...

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angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conducting conductor const constant corresponding Coulomb's law current density curve cylinder dielectric dipole direction displacement distance divergence theorem electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux free charge function given illustrated in Figure induction infinitely long integral integrand Laplace's equation line charge located Lorentz transformation magnetic magnitude Maxwell's equations normal component obtained origin parallel plate capacitor particle perpendicular point charge polarized position vector potential difference quadrupole quantities rectangular coordinates region result satisfy scalar potential shown in Figure situation solenoid solution sphere of radius spherical surface charge surface charge density surface integral tangential components theorem total charge vacuum vector potential velocity volume write written xy plane zero