Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 510
... assume that no joint displace- ments can occur . • A special staged solution process is required if joint displacements can occur . • The axial deformations of members of frames are assumed to be zero . • The moment distribution process ...
... assume that no joint displace- ments can occur . • A special staged solution process is required if joint displacements can occur . • The axial deformations of members of frames are assumed to be zero . • The moment distribution process ...
Page 615
... assume some type of deformation behavior of the structure . In Section 15.3 this involved assuming a displacement function along the member and using Castigliano's first theorem to establish the equilibrium equations for solution . For ...
... assume some type of deformation behavior of the structure . In Section 15.3 this involved assuming a displacement function along the member and using Castigliano's first theorem to establish the equilibrium equations for solution . For ...
Page 618
... Assume that all rotations at the top of the frame are the same and equal to 0. Use the minimum total potential energy principle . STEP 1 Assume displacement of u to the right at joint D and counterclockwise rotations 0 at joints D , E ...
... Assume that all rotations at the top of the frame are the same and equal to 0. Use the minimum total potential energy principle . STEP 1 Assume displacement of u to the right at joint D and counterclockwise rotations 0 at joints D , E ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ