Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 481
... substituted back into the expressions for MBA and MBC in step 3. They become [ K1 / ( K , + K2 ) ] ( wL2 / 12 ) for MBA and [ K2 / ( K , + K2 ) ] ( wL2 / 12 ) for MBC respectively , as shown in Fig . 12.1 . These same moments are listed ...
... substituted back into the expressions for MBA and MBC in step 3. They become [ K1 / ( K , + K2 ) ] ( wL2 / 12 ) for MBA and [ K2 / ( K , + K2 ) ] ( wL2 / 12 ) for MBC respectively , as shown in Fig . 12.1 . These same moments are listed ...
Page 641
... substituted into the four equations for member end forces , Eq . ( 16.1 ) . These equations , after substitution of Eq . ( 16.5 ) , can be written as a system of four equations using matrix notation . The results are AE · [ ( u ; − u ...
... substituted into the four equations for member end forces , Eq . ( 16.1 ) . These equations , after substitution of Eq . ( 16.5 ) , can be written as a system of four equations using matrix notation . The results are AE · [ ( u ; − u ...
Page 710
... substitution process establishes the solution of the remaining equations . For the system of equations that is identical to those defined in Eq . ( A.6 ) , AX = C the matrix A can be transformed into the matrix L , which is upper ...
... substitution process establishes the solution of the remaining equations . For the system of equations that is identical to those defined in Eq . ( A.6 ) , AX = C the matrix A can be transformed into the matrix L , which is upper ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ