Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
From inside the book
Results 1-3 of 87
Page 100
... applied load , P , is resolved into components parallel to the orientation of the members . The two member forces will be equal and opposite to these components of P. This condition also occurs in Example 3.2 at joint Lo . In that ...
... applied load , P , is resolved into components parallel to the orientation of the members . The two member forces will be equal and opposite to these components of P. This condition also occurs in Example 3.2 at joint Lo . In that ...
Page 249
... applied loading and the reactions developed together constitute a force system in equilibrium on the structure . Internally , stresses will de- velop that are in equilibrium with the applied force system . Now consider a set of small ...
... applied loading and the reactions developed together constitute a force system in equilibrium on the structure . Internally , stresses will de- velop that are in equilibrium with the applied force system . Now consider a set of small ...
Page 603
... applied forces and moments with a set of arbitrary displacements and rotations . The change in internal work , or sim- ply the internal work , corresponds to SU since the internal stresses associ- ated with the specified applied forces ...
... applied forces and moments with a set of arbitrary displacements and rotations . The change in internal work , or sim- ply the internal work , corresponds to SU since the internal stresses associ- ated with the specified applied forces ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ