Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 140
... concentrated load is present , the concept expressed in Eq . ( 4.4 ) can be used in the regions on either side of the load . Then , in passing from the left to the right side of the concentrated load , the shear will change by an amount ...
... concentrated load is present , the concept expressed in Eq . ( 4.4 ) can be used in the regions on either side of the load . Then , in passing from the left to the right side of the concentrated load , the shear will change by an amount ...
Page 296
... concentrated load Q = IL ( x ) · 1 IL ( x2 ) , IL ( x ; ) IL ( x7 ) 1 1 IL ( xm ) IL ( x ) m ... X PP P Pm X1 X2 Xi m Y Xm Q = Σ P ; IL ( xi ) 1 = 1 ( b ) Several concentrated loads Figure 8.1a - b Calculation of a force or moment ...
... concentrated load Q = IL ( x ) · 1 IL ( x2 ) , IL ( x ; ) IL ( x7 ) 1 1 IL ( xm ) IL ( x ) m ... X PP P Pm X1 X2 Xi m Y Xm Q = Σ P ; IL ( xi ) 1 = 1 ( b ) Several concentrated loads Figure 8.1a - b Calculation of a force or moment ...
Page 297
... concentrated load , the maximum value of Q is given when the load acts on the structure at a point where the ordi- nate to the influence line for Q is an absolute maximum . Distributed loads can act over any length of the structure . In ...
... concentrated load , the maximum value of Q is given when the load acts on the structure at a point where the ordi- nate to the influence line for Q is an absolute maximum . Distributed loads can act over any length of the structure . In ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ