Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 282
... constant ) . Include both bending and axial forces in the virtual work computation . Indicate the percentage of the final vertical deflection at a that is due to axial force effects alone . ( Hint : Convert all dimensions to inches ...
... constant ) . Include both bending and axial forces in the virtual work computation . Indicate the percentage of the final vertical deflection at a that is due to axial force effects alone . ( Hint : Convert all dimensions to inches ...
Page 513
... constant ) . 50 kN / m 2 21 TIT 2.7 m 4.8 m 12.9 Draw the final moment diagram for the structure shown . Use the moment distribution method . Neglect axial de- formations ( E constant ) . 100 kN B C 21 I 3.6 m 45 kN / m 21 12.7 Obtain ...
... constant ) . 50 kN / m 2 21 TIT 2.7 m 4.8 m 12.9 Draw the final moment diagram for the structure shown . Use the moment distribution method . Neglect axial de- formations ( E constant ) . 100 kN B C 21 I 3.6 m 45 kN / m 21 12.7 Obtain ...
Page 607
... constant axial force is analyzed approximately in the next two examples . Example 15.1 The displacement function for a prismatic member under constant axial force shown in Fig . 15.2 is used as the assumed de- formation of the member ...
... constant axial force is analyzed approximately in the next two examples . Example 15.1 The displacement function for a prismatic member under constant axial force shown in Fig . 15.2 is used as the assumed de- formation of the member ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ