Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 481
... factor for member A B at B , DBA , is DBA = K1 K1 + K2 and the distribution factor for member B - C at B is DBC = K2 K1 + K , The two distribution factors are computed and entered in the boxes on the diagram in operation 2 in Fig . 12.2 ...
... factor for member A B at B , DBA , is DBA = K1 K1 + K2 and the distribution factor for member B - C at B is DBC = K2 K1 + K , The two distribution factors are computed and entered in the boxes on the diagram in operation 2 in Fig . 12.2 ...
Page 485
... factor for member B - C being reduced to 4K2 . The reduction in the relative stiffness factor occurs because of the requirement that joint C must undergo a rotation -0/2 simultane- ously with any rotation 8 at B to preserve the zero ...
... factor for member B - C being reduced to 4K2 . The reduction in the relative stiffness factor occurs because of the requirement that joint C must undergo a rotation -0/2 simultane- ously with any rotation 8 at B to preserve the zero ...
Page 555
... factor a defined in Fig . 14.1b . As shown in Fig . 14.2 , a typical member such as i - j in a frame and under vertical load has moments develop at the ends due to the restraining effects of the columns and other beams . A value of the ...
... factor a defined in Fig . 14.1b . As shown in Fig . 14.2 , a typical member such as i - j in a frame and under vertical load has moments develop at the ends due to the restraining effects of the columns and other beams . A value of the ...
Common terms and phrases
action analysis antisymmetric applied loads assumption axial loads calculation centroidal column complementary virtual Compute concentrated load conjugate beam constant cross section curvature diagram defined deformation system direct integration displacements and rotations distributed load Draw the final end moments equations of equilibrium equilibrium equations Example Figure final moment diagram forces and moments free body hinge horizontal indeterminate structure influence line integration joint kips kN/m left end linear linear elastic loading diagram magnitude mathematical model maximum member A-B member forces ment moment distribution moment of inertia Neglect axial deformations nonlinear materials nonprismatic numerical integration panel points positive reaction components shown in Fig sign convention simply supported beam slope spreadsheet statically determinate structures STEP strain energy stress stress-strain relation struc superposition tion truss U₁ uniform load unit load vertical deflection vertical displacement virtual force system virtual work principle zero ΕΙ