Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 56
... geometrically stable . In Examples 2.1 and 2.2 it was assumed ( cor- rectly ) that the structures in those examples were geometrically stable , and hence the reactions could be computed successfully . In Sections 2.1 and 2.2 it was also ...
... geometrically stable . In Examples 2.1 and 2.2 it was assumed ( cor- rectly ) that the structures in those examples were geometrically stable , and hence the reactions could be computed successfully . In Sections 2.1 and 2.2 it was also ...
Page 91
... geometrically unstable if the number of unknowns is less than the number of equations of equilibrium . If , in a geo- metrically stable structure , the number of unknowns is equal to the number of equations of equilibrium , the ...
... geometrically unstable if the number of unknowns is less than the number of equations of equilibrium . If , in a geo- metrically stable structure , the number of unknowns is equal to the number of equations of equilibrium , the ...
Page 165
... geometrically unstable . If , in a geometrically stable frame , the number of unknowns equals the number of ... geometrically unstable p = 0 statically determinate if not geometrically unstable p > 0_statically indeterminate to degree p ...
... geometrically unstable . If , in a geometrically stable frame , the number of unknowns equals the number of ... geometrically unstable p = 0 statically determinate if not geometrically unstable p > 0_statically indeterminate to degree p ...
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acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ