Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 97
... joint , such as Uo . Continuing from joint to joint and using the two equations of equi- librium in the free body at each joint , all member forces can be obtained . The order in which the joints are considered for solution in this ...
... joint , such as Uo . Continuing from joint to joint and using the two equations of equi- librium in the free body at each joint , all member forces can be obtained . The order in which the joints are considered for solution in this ...
Page 454
... joint is part of the free- body diagram for the establishment of moment equilibrium at B. The recognition and use of the zero moment condition at D in step 2 re- duces the number of unknowns and speeds the computation process by ...
... joint is part of the free- body diagram for the establishment of moment equilibrium at B. The recognition and use of the zero moment condition at D in step 2 re- duces the number of unknowns and speeds the computation process by ...
Page 492
... joint rotation , B , and displacement , VB . The possibility of a vertical joint displacement at B prevents a direct ap- plication of the moment distribution process . A modification of the moment distribution method can be made that ...
... joint rotation , B , and displacement , VB . The possibility of a vertical joint displacement at B prevents a direct ap- plication of the moment distribution process . A modification of the moment distribution method can be made that ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ