Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 494
... solution to the problem . The desired solution , S , is a matrix of all internal member end moments and external re- actions and applied loads for the structure in Fig . 12.5a . It can be obtained by the superposition of the ...
... solution to the problem . The desired solution , S , is a matrix of all internal member end moments and external re- actions and applied loads for the structure in Fig . 12.5a . It can be obtained by the superposition of the ...
Page 495
... solution . The S solution is completed in steps 1 and 2 with the reactive force required to prevent the vertical displacement of B being computed as 144 kN in step 2. Steps 3 to 5 comprise the S , solution for an arbitrary vertical ...
... solution . The S solution is completed in steps 1 and 2 with the reactive force required to prevent the vertical displacement of B being computed as 144 kN in step 2. Steps 3 to 5 comprise the S , solution for an arbitrary vertical ...
Page 501
... solution So of Fig . 12.7b is no different from the S。 of previously worked problems , but the three potential joint displacements must be restrained with three temporary supports . There must be three additional solutions , one for ...
... solution So of Fig . 12.7b is no different from the S。 of previously worked problems , but the three potential joint displacements must be restrained with three temporary supports . There must be three additional solutions , one for ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ