Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 14
... torques , and moments for linear elastic materials is presented . The spatial distribution on the cross section of ... torques , and moments . In Fig . 1.4b a plane cross section of area A taken through a three - dimensional body ...
... torques , and moments for linear elastic materials is presented . The spatial distribution on the cross section of ... torques , and moments . In Fig . 1.4b a plane cross section of area A taken through a three - dimensional body ...
Page 17
... torque , and moment actions Txy dA = dFxy dy dA = dy dz Txz dA = dFxz Ox dA = dFx Centroid Vy X My T x dz ( c ) Element dA in y - z plane showing forces dFx , dFxy , and dFxz due to internal stresses V z M2 Z ( d ) Internal stress ...
... torque , and moment actions Txy dA = dFxy dy dA = dy dz Txz dA = dFxz Ox dA = dFx Centroid Vy X My T x dz ( c ) Element dA in y - z plane showing forces dFx , dFxy , and dFxz due to internal stresses V z M2 Z ( d ) Internal stress ...
Page 18
... torque about the centroid as shown in Fig . 1.4c and d . The torque , T , is ob- tained by integration over the cross section and is defined as T A = [ ( y dF ̧ - 2 dF , ̧ ) = [ ( 97 - z √ ( VT ZT ) dA ( 1.6 ) XZ The internal torque 7 ...
... torque about the centroid as shown in Fig . 1.4c and d . The torque , T , is ob- tained by integration over the cross section and is defined as T A = [ ( y dF ̧ - 2 dF , ̧ ) = [ ( 97 - z √ ( VT ZT ) dA ( 1.6 ) XZ The internal torque 7 ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ