Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 40
... unknown reaction components la- beled R1 , R2 , and R3 . Since there are three equilibrium equations for the planar ... unknown reaction components Three equilibrium equations ( a ) Simply supported beam Four unknown reaction components ...
... unknown reaction components la- beled R1 , R2 , and R3 . Since there are three equilibrium equations for the planar ... unknown reaction components Three equilibrium equations ( a ) Simply supported beam Four unknown reaction components ...
Page 97
... unknown member forces acting . This first occurs at joint L3 , where the only unknown member force is that for member L3 - U3 . The reason for this occurrence is the fact that three equi- librium equations were used to compute the unknown ...
... unknown member forces acting . This first occurs at joint L3 , where the only unknown member force is that for member L3 - U3 . The reason for this occurrence is the fact that three equi- librium equations were used to compute the unknown ...
Page 160
... unknown reaction components in Eqs . ( 5.1 ) are easily obtained , pro- vided that displacements Ag and A , are known . With the reaction compo- nents and the joint displacements known , free - body diagrams for members A - B , B - C ...
... unknown reaction components in Eqs . ( 5.1 ) are easily obtained , pro- vided that displacements Ag and A , are known . With the reaction compo- nents and the joint displacements known , free - body diagrams for members A - B , B - C ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ