Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 111
... vertical member force from a free body of the joint at the chord where the vertical and diagonal member join . This is illustrated in step 5 at joint U3 . For numerical computation is U.S. units , take b = 30 ft and P = 5 kips ; for SI ...
... vertical member force from a free body of the joint at the chord where the vertical and diagonal member join . This is illustrated in step 5 at joint U3 . For numerical computation is U.S. units , take b = 30 ft and P = 5 kips ; for SI ...
Page 282
... vertical deflection of a ( E constant ) . Include both bending and axial forces in the virtual work computation . Indicate the percentage of the final vertical deflection at a that is due to axial force effects alone . ( Hint : Convert ...
... vertical deflection of a ( E constant ) . Include both bending and axial forces in the virtual work computation . Indicate the percentage of the final vertical deflection at a that is due to axial force effects alone . ( Hint : Convert ...
Page 372
... Vertical displacement restraint at A removed A Hinge W B 1 ( b ) Slope continuity restraint at center of beam removed Figure 10.3a - b Alternative statically determinate forms of the structure in Fig . 10.1 . The structure shown in Fig ...
... Vertical displacement restraint at A removed A Hinge W B 1 ( b ) Slope continuity restraint at center of beam removed Figure 10.3a - b Alternative statically determinate forms of the structure in Fig . 10.1 . The structure shown in Fig ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ