Analysis and Behavior of StructuresOffering students a presentation of classical structural analysis, this text emphasizes the limitations required in creating mathematical models for analysis, including these used in computer programs. Students are encouraged to use hand methods of analysis to develop a feel for the behaviour of structures. |
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Page 41
... zero is intro- duced at the hinge . The structure of Fig 2.1c has four unknown reaction components , but there are three equations of equilibrium and one known condition of zero internal moment at the hinge . If a section is passed ...
... zero is intro- duced at the hinge . The structure of Fig 2.1c has four unknown reaction components , but there are three equations of equilibrium and one known condition of zero internal moment at the hinge . If a section is passed ...
Page 103
... zero , it can be concluded that the force in member 5-6 is also zero . Proceeding in like manner to joints 5 , 4 , and 3 leads to the conclusion that all the diagonal bracing member forces are zero , which greatly simplifies the ...
... zero , it can be concluded that the force in member 5-6 is also zero . Proceeding in like manner to joints 5 , 4 , and 3 leads to the conclusion that all the diagonal bracing member forces are zero , which greatly simplifies the ...
Page 446
... zero and rotations at points of support of beams with transverse loading are the only unknowns . All frame structures undergo some joint translation , so that a general application of the slope - deflection equations must include those ...
... zero and rotations at points of support of beams with transverse loading are the only unknowns . All frame structures undergo some joint translation , so that a general application of the slope - deflection equations must include those ...
Common terms and phrases
acting action analysis applied applied loads assumed assumptions axial force axis beam behavior bending calculation caused Chapter column components Compute condition constant continued create curvature defined deflection deformations developed direction displacement distribution Draw elastic end moments energy equal equations equilibrium equilibrium equations established Example expression Figure fixed force system frame free body function geometric gives hinge horizontal indeterminate structure influence line integration internal joint length limitations linear load magnitude material mathematical matrix maximum member forces ments method Note obtained occur plane positive presented principle Problem provides reaction relation relative rotation shear shown in Fig simple slope solution solve statically determinate STEP stiffness strain stresses structure symmetric Table tion truss unit load unknown vertical virtual yields zero ΕΙ