Strength of Materials |
From inside the book
Results 1-3 of 90
Page 87
... compute P and the total elonga- tion of the assembly . G 12 X 10 psi . Use Eq . ( 3-11 ) . Compute the equivalent spring constant as discussed in Illus . Prob . 333 . = www wwwww wwww - ( 1 ) -க் VP PROB . 340 and 341 . PROB . 342 ...
... compute P and the total elonga- tion of the assembly . G 12 X 10 psi . Use Eq . ( 3-11 ) . Compute the equivalent spring constant as discussed in Illus . Prob . 333 . = www wwwww wwww - ( 1 ) -க் VP PROB . 340 and 341 . PROB . 342 ...
Page 156
... Compute the maximum shearing stress developed in the beam . Solution : Part a . As shown on the shear diagram ( Fig ... computed from Fig . 5-27d , in which the area A ' is resolved into two strips 1 in . thick . Since a moment of area ...
... Compute the maximum shearing stress developed in the beam . Solution : Part a . As shown on the shear diagram ( Fig ... computed from Fig . 5-27d , in which the area A ' is resolved into two strips 1 in . thick . Since a moment of area ...
Page 262
... compute the moments over the supports . Ans . M240 ft - lb ; M = 146.7 ft - lb 100 lb 100 lb 200 lb 3 ' 2 ' 5 ' 10 ... Compute the support moments and reactions for the beam shown . Also compute the maximum positive bending moment . 842 ...
... compute the moments over the supports . Ans . M240 ft - lb ; M = 146.7 ft - lb 100 lb 100 lb 200 lb 3 ' 2 ' 5 ' 10 ... Compute the support moments and reactions for the beam shown . Also compute the maximum positive bending moment . 842 ...
Contents
RIVETED AND WELDED JOINTS | 39 |
TORSION | 65 |
SHEAR AND MOMENT IN BEAMS | 91 |
Copyright | |
12 other sections not shown
Other editions - View all
Common terms and phrases
acting actual allowable angle applied assumed axes axial axis beam bending carries caused centroidal circle column compressive compressive stress compute concrete consider constant cross-section deflection deformation Determine developed diagram diameter direction distance distributed effect elastic curve element equal equation equivalent expressed flange forces formula ft-lb given gives Hence horizontal ILLUSTRATIVE indicates inertia joint lb/ft length limit load material maximum method moments neutral axis normal obtain occurs plane plate position principal PROB PROBLEMS produced R₁ radius reaction reduces reference reinforced relation represents resisting respect resultant rivet shaft shearing stress shown in Fig shows simple slope Solution span spring steel strain strength Substituting supported Table tangent tensile thickness unit varies vertical wall weight whence zero