Strength of Materials |
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Page 389
... flanges of wide - flange beams or channels or other sections . The existence of this shearing stress is explained in Fig . 12–12 , which shows IP Section 2 Section 1- Fs H T2 H2 C2 - FIG . 12-12 . Lateral shear forces H1 and H2 in flanges ...
... flanges of wide - flange beams or channels or other sections . The existence of this shearing stress is explained in Fig . 12–12 , which shows IP Section 2 Section 1- Fs H T2 H2 C2 - FIG . 12-12 . Lateral shear forces H1 and H2 in flanges ...
Page 392
... flanges ) , and the horizontal flange forces H which are the resultants of the shearing stresses in the flanges computed as shown in the preceding article . It may seem surprising that the load P does not act through the longitudinal ...
... flanges ) , and the horizontal flange forces H which are the resultants of the shearing stresses in the flanges computed as shown in the preceding article . It may seem surprising that the load P does not act through the longitudinal ...
Page 393
... flange force H is the product of the average shearing stress in the flange multiplied by the flange area . Using Eq . ( a ) of Art . 12-6 , we have H = ( S. ) ave ( Area ) flange = ( 1 · Vh⋅ b ) ( be ) - Vhbat = 2 21 This value of H ...
... flange force H is the product of the average shearing stress in the flange multiplied by the flange area . Using Eq . ( a ) of Art . 12-6 , we have H = ( S. ) ave ( Area ) flange = ( 1 · Vh⋅ b ) ( be ) - Vhbat = 2 21 This value of H ...
Contents
RIVETED AND WELDED JOINTS | 39 |
TORSION | 65 |
SHEAR AND MOMENT IN BEAMS | 91 |
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acting actual allowable angle applied assumed axes axial axis beam bending carries caused centroidal circle column compressive compressive stress compute concrete consider constant cross-section deflection deformation Determine developed diagram diameter direction distance distributed effect elastic curve element equal equation equivalent expressed flange forces formula ft-lb given gives Hence horizontal ILLUSTRATIVE indicates inertia joint lb/ft length limit load material maximum method moments neutral axis normal obtain occurs plane plate position principal PROB PROBLEMS produced R₁ radius reaction reduces reference reinforced relation represents resisting respect resultant rivet shaft shearing stress shown in Fig shows simple slope Solution span spring steel strain strength Substituting supported Table tangent tensile thickness unit varies vertical wall weight whence zero