Strength of Materials |
From inside the book
Results 1-3 of 60
Page 150
... horizontal layer dce . Such shear resistance is available in a solid beam but not in a built - up beam of unconnected layers . If we extend the summation of horizontal forces down to layer fg , the resultant compressive force is ...
... horizontal layer dce . Such shear resistance is available in a solid beam but not in a built - up beam of unconnected layers . If we extend the summation of horizontal forces down to layer fg , the resultant compressive force is ...
Page 151
... horizontal unbalance , because in adding the horizontal forces from the top to these layers the equal compressive forces C , and Ts cancel out . We conclude that equal shear resistances are developed at layers fg and hk . However , this ...
... horizontal unbalance , because in adding the horizontal forces from the top to these layers the equal compressive forces C , and Ts cancel out . We conclude that equal shear resistances are developed at layers fg and hk . However , this ...
Page 153
... horizontal shearing stress , S. = V Ib . We have replaced the integral c dM y dA Ib dx V1 dM = V , the vertical ... Horizontal and Vertical Shearing Stresses . Most stu- dents are surprised to find the term vertical shear ( V ) appearing ...
... horizontal shearing stress , S. = V Ib . We have replaced the integral c dM y dA Ib dx V1 dM = V , the vertical ... Horizontal and Vertical Shearing Stresses . Most stu- dents are surprised to find the term vertical shear ( V ) appearing ...
Contents
RIVETED AND WELDED JOINTS | 39 |
TORSION | 65 |
SHEAR AND MOMENT IN BEAMS | 91 |
Copyright | |
12 other sections not shown
Other editions - View all
Common terms and phrases
acting actual allowable angle applied assumed axes axial axis beam bending carries caused centroidal circle column compressive compressive stress compute concrete consider constant cross-section deflection deformation Determine developed diagram diameter direction distance distributed effect elastic curve element equal equation equivalent expressed flange forces formula ft-lb given gives Hence horizontal ILLUSTRATIVE indicates inertia joint lb/ft length limit load material maximum method moments neutral axis normal obtain occurs plane plate position principal PROB PROBLEMS produced R₁ radius reaction reduces reference reinforced relation represents resisting respect resultant rivet shaft shearing stress shown in Fig shows simple slope Solution span spring steel strain strength Substituting supported Table tangent tensile thickness unit varies vertical wall weight whence zero