Strength of Materials |
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Page 72
... shaft 12 ft long is stressed to 8000 psi when twisted through 8 ° . If G 12 × 106 psi , compute the shaft diameter . What hp may be transmitted at 1200 rpm ? Ans . d 1.376 in . 306. A marine propeller shaft is to transmit 5000 hp at 126 ...
... shaft 12 ft long is stressed to 8000 psi when twisted through 8 ° . If G 12 × 106 psi , compute the shaft diameter . What hp may be transmitted at 1200 rpm ? Ans . d 1.376 in . 306. A marine propeller shaft is to transmit 5000 hp at 126 ...
Page 73
... shaft shown is at- tached to rigid supports . Segment AB is of aluminum , for which S , ≤ 4000 psi and G = 4 × 106 ... shaft is attached to rigid supports . shaft 3 in . in diameter with maximum S 10,000 psi and BC is a solid steel ...
... shaft shown is at- tached to rigid supports . Segment AB is of aluminum , for which S , ≤ 4000 psi and G = 4 × 106 ... shaft is attached to rigid supports . shaft 3 in . in diameter with maximum S 10,000 psi and BC is a solid steel ...
Page 74
... shaft . Hint : Use the results of Prob . 315 and apply superposition . a = 317. A hollow aluminum shaft of 3 in . outer diameter and 2 in . inner diameter is slipped over a solid steel shaft 2 in . in diameter and of the same length as ...
... shaft . Hint : Use the results of Prob . 315 and apply superposition . a = 317. A hollow aluminum shaft of 3 in . outer diameter and 2 in . inner diameter is slipped over a solid steel shaft 2 in . in diameter and of the same length as ...
Contents
RIVETED AND WELDED JOINTS | 39 |
TORSION | 65 |
SHEAR AND MOMENT IN BEAMS | 91 |
Copyright | |
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acting actual allowable angle applied assumed axes axial axis beam bending carries caused centroidal circle column compressive compressive stress compute concrete consider constant cross-section deflection deformation Determine developed diagram diameter direction distance distributed effect elastic curve element equal equation equivalent expressed flange forces formula ft-lb given gives Hence horizontal ILLUSTRATIVE indicates inertia joint lb/ft length limit load material maximum method moments neutral axis normal obtain occurs plane plate position principal PROB PROBLEMS produced R₁ radius reaction reduces reference reinforced relation represents resisting respect resultant rivet shaft shearing stress shown in Fig shows simple slope Solution span spring steel strain strength Substituting supported Table tangent tensile thickness unit varies vertical wall weight whence zero