Mechanics of MaterialsThis text provides a clear, comprehensive presentation of both the theory and applications of mechanics of materials. The text examines the physical behaviour of materials under load, then proceeds to model this behaviour to development theory. The contents of each chapter are organized into well-defined units that allow instructors great flexibility in course emphasis. writing style, cohesive organization, and exercises, examples, and free body diagrams to help prepare tomorrow's engineers. The book contains over 1,700 homework problems depicting realistic situations students are likely to encounter as engineers. These illustrated problems are designed to stimulate student interest and enable them to reduce problems from a physical description to a model or symbolic representation to which the theoretical principles may be applied. The problems balance FPS and SI units and are arranged in an increasing order of difficulty so students can evaluate their understanding of the material. |
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Page 291
... neutral axis must be zero . This condition can only be satisfied if the neutral axis is also the horizontal centroidal axis for the cross sec- tion . * Consequently , once the centroid for the member's cross - sectional area is ...
... neutral axis must be zero . This condition can only be satisfied if the neutral axis is also the horizontal centroidal axis for the cross sec- tion . * Consequently , once the centroid for the member's cross - sectional area is ...
Page 292
... neutral axis . We symbolize its value as I. Hence , Eq . 6-11 can be solved for max and written in general form as ... neutral axis M = the resultant internal moment , determined from the method of sections and the equations of ...
... neutral axis . We symbolize its value as I. Hence , Eq . 6-11 can be solved for max and written in general form as ... neutral axis M = the resultant internal moment , determined from the method of sections and the equations of ...
Page 311
... Neutral Axis . The angle a of the neutral axis in Fig . 6-34d can be determined by applying Eq . 6-17 with σ = 0 , since by definition no normal stress acts on the neutral axis . We have y Mylzz M2ly = M sin 0 , then Since M2 = M cos 0 ...
... Neutral Axis . The angle a of the neutral axis in Fig . 6-34d can be determined by applying Eq . 6-17 with σ = 0 , since by definition no normal stress acts on the neutral axis . We have y Mylzz M2ly = M sin 0 , then Since M2 = M cos 0 ...
Common terms and phrases
allowable shear stress aluminum angle of twist Applying Eq average normal stress average shear stress axial force axial load beam beam's bolt caused centroid column compressive computed constant cross section cross-sectional area deflection deformation Determine the average determine the maximum displacement distributed load elastic curve example factor of safety free-body diagram ft Prob Hooke's law in² internal torque kN·m kN/m length linear-elastic loading shown material maximum shear stress mm² modulus of elasticity Mohr's circle moment of inertia neutral axis plane plastic positive principal stresses radius sectional area segment shear force shear strain shear-stress distribution shown in Fig sign convention slope SOLUTION statically indeterminate stress acting stress components stress developed stress distribution stress is Tallow stress-strain diagram subjected Tallow Tavg tensile tensile stress thickness tion Tmax torque torsional tube vertical wire yield zero ΕΙ