Strength of Materials |
From inside the book
Results 1-3 of 89
Page 117
... PROB . 429 . 9 ' . 22 180 lb / ft R2 R1 PROB . 431 . PROB . 430 . 12 ' 100 lb / ft R1 R2 PROB . 432 . 3 ' R1 6 ' PROB . 433 . 240 lb / ft R1 4 ' R2 PROB . 434 . 430. Beam loaded as shown . 431. Beam loaded as shown . 432. Beam loaded as ...
... PROB . 429 . 9 ' . 22 180 lb / ft R2 R1 PROB . 431 . PROB . 430 . 12 ' 100 lb / ft R1 R2 PROB . 432 . 3 ' R1 6 ' PROB . 433 . 240 lb / ft R1 4 ' R2 PROB . 434 . 430. Beam loaded as shown . 431. Beam loaded as shown . 432. Beam loaded as ...
Page 218
... PROB . 660 . 661. For the beam described in Prob . 647 ( page 204 ) , divide the distributed load into three equal parts , and replace each part by its resultant of 48 lb. Compute the midspan deflection of these three concentrated loads ...
... PROB . 660 . 661. For the beam described in Prob . 647 ( page 204 ) , divide the distributed load into three equal parts , and replace each part by its resultant of 48 lb. Compute the midspan deflection of these three concentrated loads ...
Page 269
... PROB . 849 . R1 -12'- R2 850. Determine the value of P that will cause zero deflection under P. 851. Determine the value of the midspan Ely . = Ans . P 202.5 lb Ans . Ely = 5570 lb - ft3 R1 60 lb / ft 12 ' P R2 R1 PROB . 850 . 30 lb ...
... PROB . 849 . R1 -12'- R2 850. Determine the value of P that will cause zero deflection under P. 851. Determine the value of the midspan Ely . = Ans . P 202.5 lb Ans . Ely = 5570 lb - ft3 R1 60 lb / ft 12 ' P R2 R1 PROB . 850 . 30 lb ...
Contents
SIMPLE STRESS | 1 |
RIVETED AND WELDED JOINTS | 39 |
TORSION | 65 |
Copyright | |
24 other sections not shown
Other editions - View all
Common terms and phrases
acting AISC formula allowable stresses angle applied area-moment method assumed axes axial load beam shown bending bending moment C₁ C₂ Carry-over centroidal column formula compressive stress Compute the maximum concrete continuous beam critical load cross-section deflection deformation Determine the maximum diameter elastic curve element end moments equal equivalent Euler's Euler's formula factor of safety fixed end flange flexural stress ft long ft-lb Hence ILLUSTRATIVE PROBLEMS in.¹ lb-ft³ lb/ft length M₁ M₂ maximum shearing stress maximum stress midspan Mohr's circle moment of inertia moments of inertia neutral axis normal stress obtain P₁ plane plate principal stresses PROB product of inertia proportional limit R₂ radius resultant rivet shaft shear center shear diagram shown in Fig simply supported slenderness ratio slope Solution span steel strain tangent tensile stress three-moment equation torsional vertical shear whence zero ΕΙ