Strength of Materials |
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Page 28
... aluminum or 14,000 psi for brass ? Can a larger load P be carried if the length of the aluminum rod is increased while keeping the length of the brass rod constant ? If so , to what value should La be changed ? Ans . ( a ) P 26,800 lb ...
... aluminum or 14,000 psi for brass ? Can a larger load P be carried if the length of the aluminum rod is increased while keeping the length of the brass rod constant ? If so , to what value should La be changed ? Ans . ( a ) P 26,800 lb ...
Page 35
... aluminum cylinder . The copper rod projects 0.005 in . , as shown in Fig . 1-17 . What maxi- mum load P may be applied to the bearing plate ? Use the data in the following table : Copper Bearing P plate 10 " Copper rod FIG . 1-17 . Aluminum ...
... aluminum cylinder . The copper rod projects 0.005 in . , as shown in Fig . 1-17 . What maxi- mum load P may be applied to the bearing plate ? Use the data in the following table : Copper Bearing P plate 10 " Copper rod FIG . 1-17 . Aluminum ...
Page 74
... aluminum shaft of 3 in . outer diameter and 2 in . inner diameter is slipped over a solid steel shaft 2 in . in diameter and of the same length as the hollow shaft . The two are then fastened rigidly together at their ends . Determine ...
... aluminum shaft of 3 in . outer diameter and 2 in . inner diameter is slipped over a solid steel shaft 2 in . in diameter and of the same length as the hollow shaft . The two are then fastened rigidly together at their ends . Determine ...
Contents
SIMPLE STRESS | 1 |
RIVETED AND WELDED JOINTS | 39 |
TORSION | 65 |
Copyright | |
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acting AISC formula allowable stresses angle applied assumed axes axial load bending bending moment C₁ C₂ Carry-over centroidal column formula compressive stress Compute the maximum concrete critical load cross-section deflection deformation Determine the maximum diameter elastic curve element end moments equal equivalent Euler's formula factor of safety flange flexural stress flexure formula ft long ft-lb Hence ILLUSTRATIVE PROBLEMS in.¹ lb-ft³ lb/ft length maximum shearing stress maximum stress midspan modulus Mohr's circle moment of inertia moments of inertia neutral axis normal stress obtain P₁ plane plate principal stresses PROB product of inertia proportional limit R₁ R₂ radius reinforced resisting resultant rivet S₂ shaft shear center shear diagram shear flow shearing force shown in Fig simply supported slenderness ratio slope Solution span steel strain tangent tensile stress torsional vertical shear whence zero ΕΙ