## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh and Twelfth |

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Page 6

And that a circle may be

And that a circle may be

**described**from any centre , at any distance from that centre . a AXIOMS . I. THINGS which are equal to the same thing , are equal to one another . II . If equals be added to equals , the wholes are equal . III . Page 8

... BC are equal to one another : and the triangle ABC is therefore equilateral , and it is

... BC are equal to one another : and the triangle ABC is therefore equilateral , and it is

**described**upon the given straight line AB . Which was required to be done . PROP . II . PROB . From a given point to draw a straight line equal ... Page 42

... angles CEF equalt to the given angle D : wherefore a parallelogram FECG has been

... angles CEF equalt to the given angle D : wherefore a parallelogram FECG has been

**described**equal to the given triangle ABC , having one of its angles CEF equal to the given angle D. Which was to be done . Me # PROP . XLIII . THEOR . Page 45

Therefore the parallelogram KFLM has been

Therefore the parallelogram KFLM has been

**described**equal to the given rectilineal . figure ABCD , having the angle FKM equal to the given angle E. Which was to be done . OR . - From thi t is manifest how to a given straight line to ... Page 46

In any right - angled triangle , the square which is

In any right - angled triangle , the square which is

**described**upon the side subtending the right angle , is equal to the squares**described**upon the sides which contain the right angle . Let ABC be a right - angled triangle having * 14 ...### What people are saying - Write a review

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The Elements of Euclid: Viz. The First Six Books, Together With the Eleventh ... Euclid Euclid No preview available - 2018 |

### Common terms and phrases

altitude angle ABC angle BAC base base BC BC is equal centre circle ABCD circumference common cone Const contained cylinder demonstrated described diameter divided double draw drawn equal angles equiangular equilateral equimultiples extremities fall figure fore four fourth given given straight line greater half inscribed join less Let ABC likewise magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism PROB produced PROP proportionals proved pyramid ratio reason rectangle contained rectilineal figure remaining angle right angles segment shown sides similar solid solid angle solid parallelopiped sphere square taken THEOR third touches triangle ABC vertex wherefore whole