## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh and Twelfth |

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Page 16

... CD , each to each ; and the angle ACD is † Const . equal t to the angle BCD ; therefore the base AĎ is equal to the A D B base * DB , and the straight line AB is

... CD , each to each ; and the angle ACD is † Const . equal t to the angle BCD ; therefore the base AĎ is equal to the A D B base * DB , and the straight line AB is

**divided**into two equal parts in the point D. Which was to be done . Page 34

For any rectilineal figure ABCDE , can be

For any rectilineal figure ABCDE , can be

**divided**into as many triangles as the figure has sides , by drawing straight lines from a point F within the figure to each of its angles . And , by the preceding proposition , all the angles of ... Page 50

If there be two straight lines , one of which is

If there be two straight lines , one of which is

**divided**into any number of parts ; the rectangle contained by the two straight lines , is equal to the rectangles contained by the undivided line , and the several parts of the**divided**... Page 51

If a straight line be

If a straight line be

**divided**into any two parts , the rectangle contained by the whole and one of the parts , is equal to the rectangle contained by the two parts , together with the square of the aforesaid part . Page 52

If a straight line be

If a straight line be

**divided**into any two parts , the square of the whole line is equal to the squares of the two parts , together with twice the rectangle contained by the parts . Let the straight line AB be**divided**into any two parts ...### What people are saying - Write a review

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The Elements of Euclid: Viz. The First Six Books, Together With the Eleventh ... Euclid Euclid No preview available - 2018 |

### Common terms and phrases

altitude angle ABC angle BAC base base BC BC is equal centre circle ABCD circumference common cone Const contained cylinder demonstrated described diameter divided double draw drawn equal angles equiangular equimultiples fall figure fore four fourth given given straight line greater half inscribed join less Let ABC likewise magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism PROB produced PROP proportionals proved pyramid Q. E. D. PROP ratio reason rectilineal figure remaining angle right angles segment shown sides similar solid solid angle solid parallelopiped sphere square taken THEOR third touches triangle ABC vertex wherefore whole