## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh and Twelfth |

### From inside the book

Results 1-5 of 39

Page 12

Hence every equilateral triangle is also

Hence every equilateral triangle is also

**equiangular**. 3 PROP . VI . THEOR , If two angles of a triangle be egual to one another , the sides also which subtend or are opposite to the equal angles , shall be equal to one another . Page 13

Hence every

Hence every

**equiangular**triangle is also equilateral . PROP . VII . THEOR . Upon the same base , and on the same side of it , there cannot be two triangles that have their sides , which are terminated in one extremity of the base ... Page 108

Which was to be done . 1 . PROP . II . PROB . * 17.3 . In a given circle to inscribe a triangle

Which was to be done . 1 . PROP . II . PROB . * 17.3 . In a given circle to inscribe a triangle

**equiangular**to a given triangle . Let ABC be the given circle , and DEF the given triangle ; it is required to inscribe in ... Page 109

1 . remaining angle EDF : wherefore the triangle ABC is

1 . remaining angle EDF : wherefore the triangle ABC is

**equiangular**to the triangle DEF , and it is inscribed in the circle ABC . Which was to be done . and 1 Ax . PROP . III . PROB . About a given circle to describe a triangle ... Page 110

1. fore the remaining angle MLN is equal * to the remaining angle EDF : therefore the triangle LMN is

1. fore the remaining angle MLN is equal * to the remaining angle EDF : therefore the triangle LMN is

**equiangular**to the triangle DEF : and it is described about the circle ABC . Whichi was to be done . and 3 Ax . PROP . IV . PROB .### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Other editions - View all

The Elements of Euclid: Viz. The First Six Books, Together With the Eleventh ... Euclid Euclid No preview available - 2018 |

### Common terms and phrases

altitude angle ABC angle BAC base base BC BC is equal centre circle ABCD circumference common cone Const contained cylinder demonstrated described diameter divided double draw drawn equal angles equiangular equilateral equimultiples extremities fall figure fore four fourth given given straight line greater half inscribed join less Let ABC likewise magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism PROB produced PROP proportionals proved pyramid ratio reason rectangle contained rectilineal figure remaining angle right angles segment shown sides similar solid solid angle solid parallelopiped sphere square taken THEOR third touches triangle ABC vertex wherefore whole