## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh and Twelfth |

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Page 8

To describe an equilateral triangle upon a given finite straight line . Let AB be the

To describe an equilateral triangle upon a given finite straight line . Let AB be the

**given straight line**; it is required to describe an equilateral triangle upon AB . From the centre A , at the * 3 Pos . distance AB , describe * the ... Page 9

Wherefore from the given point A a straight line AL has been drawn equal to the

Wherefore from the given point A a straight line AL has been drawn equal to the

**given straight line**BC . Which was to be done . * 3 Ax , PROP . III . PROB . G * 2.1 . From the greater of two**given straight lines**to cut off a part equal ... Page 15

gle ABC be applied to DEF , so that the point B be on E , and the

gle ABC be applied to DEF , so that the point B be on E , and the

**straight line**BC upon EF ; the point C shall also coincide with the point F ... To bisect a**given**rectilineal angle , that is , to divide it into two equal angles . Page 16

1 . bisected by the straight line AF . Which was to be done . PROP . X. PROB . To bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the

1 . bisected by the straight line AF . Which was to be done . PROP . X. PROB . To bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the

**given straight line**; it is required to divide it into ... Page 17

Wherefore , from the given point C , in the

Wherefore , from the given point C , in the

**given straight line**AB , FC has been drawn at right angles to AB . Which was to be done . Cor . - By help of this problem , it may be demonstrated , that two straight lines cannot have a ...### What people are saying - Write a review

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The Elements of Euclid: Viz. The First Six Books, Together With the Eleventh ... Euclid Euclid No preview available - 2018 |

### Common terms and phrases

altitude angle ABC angle BAC base base BC BC is equal centre circle ABCD circumference common cone Const contained cylinder demonstrated described diameter divided double draw drawn equal angles equiangular equilateral equimultiples extremities fall figure fore four fourth given given straight line greater half inscribed join less Let ABC likewise magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism PROB produced PROP proportionals proved pyramid ratio reason rectangle contained rectilineal figure remaining angle right angles segment shown sides similar solid solid angle solid parallelopiped sphere square taken THEOR third touches triangle ABC vertex wherefore whole