## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh and Twelfth |

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Page 3

“ A

“ A

**segment**of a circle is the figure contained ' by a straight line , and the circumference it cuts off . ” * 7 XX . Rectilineal figures are those which are contained by B 2 BOOK I. -DEFINITIONS . 3 XII. ... Page 17

By help of this problem , it may be demonstrated , that two straight lines cannot have a common

By help of this problem , it may be demonstrated , that two straight lines cannot have a common

**segment**. If it be possible , let the two straight lines ABC , ABD have the**segment**AB common to both of them . Page 68

A

A

**segment**of a circle is the figure contained by a straight line and the circumference it cuts off . VII . “ The angle of a**segment**is that which is contained by the straight line and the circumference . " VIII . An angle in a**segment**... Page 69

Similar

Similar

**segments**of circles are those in which the angles are equal , or which contain equal angles . PROP . I. PROB . # * 10.1 . * 11.1 . To find the centre of a given circle . Let ABC be the given circle ; it is required to find its ... Page 88

Let ABCD be a circle , and BAD , BED angles in the same

Let ABCD be a circle , and BAD , BED angles in the same

**segment**BAED : the angles BAD , BED shall be equal to one another . B First , let the**segment**BAED be greater than a semicircle . + 1.3 . Take + F , the centre of the circle ABCD ...### What people are saying - Write a review

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The Elements of Euclid: Viz. The First Six Books, Together With the Eleventh ... Euclid Euclid No preview available - 2018 |

### Common terms and phrases

altitude angle ABC angle BAC base base BC BC is equal centre circle ABCD circumference common cone Const contained cylinder demonstrated described diameter divided double draw drawn equal angles equiangular equilateral equimultiples extremities fall figure fore four fourth given given straight line greater half inscribed join less Let ABC likewise magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism PROB produced PROP proportionals proved pyramid ratio reason rectangle contained rectilineal figure remaining angle right angles segment shown sides similar solid solid angle solid parallelopiped sphere square taken THEOR third touches triangle ABC vertex wherefore whole