## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh and Twelfth |

### From inside the book

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Page 7

The

The

**whole**is greater than its part . X. Two straight lines cannot inclose a space . XI . All right angles are equal to one another . XII . • If a straight line meets two straight lines , so as to make the two interior angles on the same ... Page 10

Therefore the base BC coincides with the base EF , and 18 Ax . therefore is equal t to it . Wherefore the

Therefore the base BC coincides with the base EF , and 18 Ax . therefore is equal t to it . Wherefore the

**whole**triangle ABC coincides with the**whole**triangle DEF , and is equal to it ; and the io EUCLID'S ELEMENTS . AA ... Page 12

CGB ; angle ABG , and the angle AFC to the angle AGB : and because the

CGB ; angle ABG , and the angle AFC to the angle AGB : and because the

**whole**AF is equal to the**whole**AG , of which the parts AB , AC , are * 3 Ax . equal ; the remainder BF is equal * to the remainder CG ; and FC was proved to be equal ... Page 23

... same manner it may be BE To make a tym Leth , B. hu HT. I Because AD is equal t to AC , add BA to each , therefore + Const the

... same manner it may be BE To make a tym Leth , B. hu HT. I Because AD is equal t to AC , add BA to each , therefore + Const the

**whole**BD is equal t to the two BA and AC . 1 2 Ax . * 16. 1 . apa line F da giren uke Воск І. 23 PROP . XX . Page 34

1. angle ECD is equal tto the interior and opposite angle ABC : but the angle ACE was shown to be equal to the angle BAC ; therefore the

1. angle ECD is equal tto the interior and opposite angle ABC : but the angle ACE was shown to be equal to the angle BAC ; therefore the

**whole**+2 Ax .. exterior angle ACD is equal † to the two interior and opposite angles CAB , ABC : to ...### What people are saying - Write a review

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The Elements of Euclid: Viz. The First Six Books, Together With the Eleventh ... Euclid Euclid No preview available - 2018 |

### Common terms and phrases

altitude angle ABC angle BAC base base BC BC is equal centre circle ABCD circumference common cone Const contained cylinder demonstrated described diameter divided double draw drawn equal angles equiangular equimultiples fall figure fore four fourth given given straight line greater half inscribed join less Let ABC likewise magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism PROB produced PROP proportionals proved pyramid Q. E. D. PROP ratio reason rectilineal figure remaining angle right angles segment shown sides similar solid solid angle solid parallelopiped sphere square taken THEOR third touches triangle ABC vertex wherefore whole