## Strength of Materials |

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Page 84

Compute the number of turns required to permit a stretch of 4 in. without

exceeding a shearing stress of 20,000 psi. Use Eq. (3-9) and G = 12 X 106 psi.

Ans. n = 16.7 turns 346.

Compute the number of turns required to permit a stretch of 4 in. without

exceeding a shearing stress of 20,000 psi. Use Eq. (3-9) and G = 12 X 106 psi.

Ans. n = 16.7 turns 346.

**Compute the maximum**shearing stress developed in a ...Page 123

With this rule we locate the position of each load when the moment at that load is

a

With this rule we locate the position of each load when the moment at that load is

a

**maximum**, and**compute**the value of each such**maximum**moment. The**maximum**shearing force occurs at, and is equal to, the**maximum**reaction.Page 125

Max. M = 48.0 ton-ft; max. V = 8.0 tons 461. Repeat Prob. 460, using axle loads of

2 tons and 4 tons on a wheel base of 12 ft crossing a 20-ft span. 462. A tractor ...

**Compute the maximum**bending moment and the maximum shearing force. Ans.Max. M = 48.0 ton-ft; max. V = 8.0 tons 461. Repeat Prob. 460, using axle loads of

2 tons and 4 tons on a wheel base of 12 ft crossing a 20-ft span. 462. A tractor ...

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acting actual allowable angle applied assumed axes axis beam shown bending bending moment cantilever carries caused centroid circle CN CN column compressive compressive stress compute concentrated consider constant couple cross section deflection deformation Determine developed diameter direction distance distributed distributed load effect elastic curve element equal equation equivalent expressed flange flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia lb/ft length limit load loaded as shown material maximum method midspan moments negative neutral axis obtain occurs plane plate positive Prob PROBLEMS produce reaction reference relation resisting respect restrained resultant rivet segment shear diagram shearing stress shown in Fig shows simply supported slope Solution Solve span steel strain strength supported Table tangent tensile thickness varies vertical wall weight weld yield zero