## Strength of materials |

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Page 175

If the allowable strength of the glue is 75 psi, what maximum flexure stress may

be developed when supporting a uniformly distributed load on a 12-ft simple

span? 582. A rectangular beam 6 in. wide by 10 in. high supports a total

distributed load of W lb and a concentrated load of 211' lb applied as shown in

Fig. P-582. If S i£ 1500 psi and S, ^ 120 psi,

Ans. W = 2220lb 1ZZZZE2ZZ2A L 21V lb 9' I 3' Wlb -12' -1" mzz^zzzm i" 10" 8't Fig

. P-582. Fig.

If the allowable strength of the glue is 75 psi, what maximum flexure stress may

be developed when supporting a uniformly distributed load on a 12-ft simple

span? 582. A rectangular beam 6 in. wide by 10 in. high supports a total

distributed load of W lb and a concentrated load of 211' lb applied as shown in

Fig. P-582. If S i£ 1500 psi and S, ^ 120 psi,

**determine the maximum**value of W.Ans. W = 2220lb 1ZZZZE2ZZ2A L 21V lb 9' I 3' Wlb -12' -1" mzz^zzzm i" 10" 8't Fig

. P-582. Fig.

Page 193

carrying a concentrated load P at midspan. Ans. S = — — 606.

uniformly distributed load of w lb/ft applied over its entire i 5 wLi 5 WL* length.

Ans. S = = 384 EI 384 EI 607.

cantilever beam loaded as shown in Fig. P-607. Take the origin at the wall. w lb/ft

- Fig. P-607. Fig.

**Determine the maximum**deflection 5 in a simply supported beam of PL3 length Lcarrying a concentrated load P at midspan. Ans. S = — — 606.

**Determine the****maximum**deflection 5 in a simply supported beam of length L carrying auniformly distributed load of w lb/ft applied over its entire i 5 wLi 5 WL* length.

Ans. S = = 384 EI 384 EI 607.

**Determine the maximum**value of EIy for thecantilever beam loaded as shown in Fig. P-607. Take the origin at the wall. w lb/ft

- Fig. P-607. Fig.

Page 416

Using the AISC formula and Eq. (11-21), compute the maximum load that can be

carried at an eccentricity of 5 in. from the geometric axis. The column also carries

a central load of 12,000 lb. Ans. P = 6350 lb 1137. A steel pipe 8 ft long, built in at

its lower end and free at its upper end, supports a sign whose center of gravity is

2 ft from the axis of the pipe.

AISC formula and Eq. (11-22), with Sb = 18,000 psi. Apply the concept of an ...

Using the AISC formula and Eq. (11-21), compute the maximum load that can be

carried at an eccentricity of 5 in. from the geometric axis. The column also carries

a central load of 12,000 lb. Ans. P = 6350 lb 1137. A steel pipe 8 ft long, built in at

its lower end and free at its upper end, supports a sign whose center of gravity is

2 ft from the axis of the pipe.

**Determine the maximum**weight of the sign; use theAISC formula and Eq. (11-22), with Sb = 18,000 psi. Apply the concept of an ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero