## Strength of materials |

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Results 1-3 of 81

Page 140

519,

distributed load that can then be carried. Ans. W = 116,000lb 522. In the portion

of a butt joint shown in Fig. P-522, a 1^-in. rivet secures J-in. cover plates to a J-in

.

519,

**determine**the optimum position of the supports and the**maximum**totaldistributed load that can then be carried. Ans. W = 116,000lb 522. In the portion

of a butt joint shown in Fig. P-522, a 1^-in. rivet secures J-in. cover plates to a J-in

.

Page 175

Express the maximum S, in terms of the maximum S/. . hS/ Ans. i>, = 24L ... If S i£

1500 psi and S, ^ 120 psi,

1ZZZZE2ZZ2A L 21V lb 9' I 3' Wlb -12' -1" mzz^zzzm i" 10" 8't Fig. P-582. Fig.

Express the maximum S, in terms of the maximum S/. . hS/ Ans. i>, = 24L ... If S i£

1500 psi and S, ^ 120 psi,

**determine the maximum**value of W. Ans. W = 2220lb1ZZZZE2ZZ2A L 21V lb 9' I 3' Wlb -12' -1" mzz^zzzm i" 10" 8't Fig. P-582. Fig.

Page 416

, with Sb = 18,000 psi. Apply the concept of an effective length. The outside

diameter of the pipe is 5.56 in., its area is 4.30 in.2, and its moment of inertia is

15.2 ...

**Determine the maximum**weight of the sign; use the AISC formula and Eq. (11-22), with Sb = 18,000 psi. Apply the concept of an effective length. The outside

diameter of the pipe is 5.56 in., its area is 4.30 in.2, and its moment of inertia is

15.2 ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero