## Strength of materials |

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Page 110

the shear area to the right of such sections, or to apply the basic definition M = (

2M)r; whence in terms of the loads acting to the right of C we find Mc = 1200 X 3 ...

**Hence**at sections near the right end of the beam, it is usually preferable to usethe shear area to the right of such sections, or to apply the basic definition M = (

2M)r; whence in terms of the loads acting to the right of C we find Mc = 1200 X 3 ...

Page 203

we obtain diagram (d). The shaded area of diagram (d) is evidently equal to the

area of the conventional moment diagram (e) obtained by plotting the resultant ...

**Hence**, if the triangular area is revolved about the line of zero moment as an axis,we obtain diagram (d). The shaded area of diagram (d) is evidently equal to the

area of the conventional moment diagram (e) obtained by plotting the resultant ...

Page 481

To prevent twisting, the resultant Vr of the flange shears must be equal, opposite,

and collinear with the external shear V.

center C, we have VM = V2b2 (b) Another relation between Vi and V2 may be ...

To prevent twisting, the resultant Vr of the flange shears must be equal, opposite,

and collinear with the external shear V.

**Hence**, taking moments about the shearcenter C, we have VM = V2b2 (b) Another relation between Vi and V2 may be ...

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allowable stresses aluminum angle assumed axes axial load beam in Fig beam loaded beam shown bending bolt cantilever beam caused centroid CN CN column compressive stress Compute the maximum concentrated load concrete cover plate cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence hinged Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan midspan deflection modulus Mohr's circle moments of inertia neutral axis obtain plane plastic positive product of inertia proportional limit radius ratio reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero